Some interesting ideas here.... Question for Dan Preston. Regarding your pulsed supplies.. What portion of the your total current, which seems remarkably high, is displacement current? We must remember that the ions are not electrons, which at 20 kev, would move at less than 0.5c. Deuterium ions would move about 60 times slower yet. This means that a few nano second pulse will give a lot less than 20 kev to the ions, since they will have moved only a few percent of the distance to the anode by the time the pulse ends. With capacitances of a few pF for the chamber innards, and a few 10's of pF for drive cables, a capacitive load current would be given by i(t) = 1/C dV/dt. With a rise time of pS,and peak voltages of 20 kV, displacement currents could easily be a 100 amperes.
Dave Cooper.
Created on Saturday, December 23, 2000 2:30 AM EDT by David Cooper